SASInstitute A00-215 Web-based Practice Exam

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SASInstitute A00-215, also known as the SAS Certified Associate: Programming Fundamentals Using SAS 9.4 Exam, is designed for individuals who want to validate their knowledge of SAS programming fundamentals. SAS Certified Associate: Programming Fundamentals Using SAS 9.4 certification exam is intended for beginners who want to learn the basics of SAS programming language and its applications.

SASInstitute SAS Certified Associate: Programming Fundamentals Using SAS 9.4 Sample Questions (Q77-Q82):

NEW QUESTION # 77
Given the program below:

Why does the program fail?

A. You cannot output to different data sets
B. You must use two different DATA statements for HEIGHT1 and HEIGHT2
C. You cannot use numbers in data set names.
D. You must include the data set height2 in the DATA statement

Answer: B

NEW QUESTION # 78
You have a dataset with student exam scores. Each student has multiple exam scores, and you need to calculate the average score for each student, but only for their top three highest scores. You need to use the FIRST. And LAST. variables within BY group processing to achieve this. Which of the following code snippets would correctly calculate the average of the top three highest scores for each student?

A. data student_avg; set exam_scores; by student_id; retain top_scores 0 count 0; if firststudent_id then do; top_scores=0; count=0; end; if _ N <=3 then do; top_scores+score; count+l; end; output; run;
B. data student_avg; set exam_scores; by student_id; retain top_scores 0 count 0; if firststudent_id then do; top_scores=0; count=0; end; array top_scores[3] _ temporary_; if _N <=3 then do; top_scores[_N_]=score; count+l; end; avg_score=sum(of top_scores[,])/count; output; run;
C. data student_avg; set exam_scores; by student_id; retain top_scores 0 count 0; if firststudent_id then do; top_scores=0; count=0; end; if _ N <=3 then do; top_scores+score; count+l; end; output; run;
D. data student_avg; set exam_scores; by student_id; retain top_scores 0 count 0; if firststudent_id then do; top_scores=0; count=0; end; if _ N <=3 then do; top_scores=score; count+l; end; avg_score=top_scores/count; output; run;
E. data student_avg; set exam_scores; by student_id; retain top_scores 0 count 0; if firststudent_id then do; top_scores=0; count=0; end; if _ N <=3 then do; top_scores+score; count+l; end; avg_score=top_scores/count; output; run;

Answer: B

Explanation:
Option C is the correct answer because it creates an array 'top_scores' to store the top three scores and uses the 'sum' function to calculate the sum of those three scores. Options A, B, D, and E either incorrectly calculate the average of all scores within the group or incorrectly store and process the top three scores_ It is crucial to ensure that the array 'top_scores' is declared as '_temporary_' to avoid carrying the array over to the next student group.

NEW QUESTION # 79
You're analyzing a dataset containing customer satisfaction ratings (1-5) and want to create a report showing the frequency distribution of ratings. However, you want the report to display the 'Excellent' (5) rating at the top and 'Poor' (1 ) rating at the bottom. Which PROC FREQ statement would achieve this?

Answer: E

Explanation:
The correct answer is E. The ORDER=(INTERNAL DESCENDING) option sorts the rows in descending order based on the internal storage order of the variable 'Rating'. Since the internal storage order would likely assign lower values to 'Poor' (1) and higher values to 'Excellent' (5), this achieves the desired result of 'Excellent' at the top and 'Poor' at the bottom. The other options are incorrect: A (ORDER-FREQ): Sorts rows by frequency, from highest to lowest. It might not match the desired order. B (ORDER-DATA): Sorts rows based on their order in the dataset. It might not match the desired order. C (ORDER-DESCENDING): Sorts rows by internal storage order but in descending order. This would result in the 'Poor' rating at the top. D (ORDER-FORMATTED): Sorts rows based on the formatted values, which might not match the desired order.

NEW QUESTION # 80
Consider two datasets, 'EMPLOYEES' and 'DEPARTMENTS', both containing a 'DEPARTMENT ID' variable. You want to combine these datasets horizontally, but only for employees in 'EMPLOYEES' whose 'HIRE DATE' is before 01JAN2010. How would you modify the MERGE statement to include this condition?

Answer: C

Explanation:
Option C is the correct solutiom It uses ' IN=' options for both datasets and an 'IF' statement to filter for records where both 'EMPLOYEES' and 'DEPARTMENTS datasets contribute a record (indicated by 'EMP' and 'DEP' being true) and the 'HIRE_DATE' in 'EMPLOYEES' is before OlJAN2010_ The 'THEN OUTPUT clause ensures only the filtered records are written to the output dataset.

NEW QUESTION # 81
You have a dataset named 'Customers' with a variable 'Region' containing region names. You want to generate a frequency report for 'Region' where the regions are ordered alphabetically. Which PROC FREQ statement correctly achieves this?

Answer: E

Explanation:
The ORDER: option in PROC FREQ allows you to control the order of the rows in the frequency report. ORDER-ALPHA specifically sorts the rows alphabetically. The other options are incorrect: A (ORDER=FREQ): Orders rows by frequency highest to lowest. B (ORDER-DATA): Orders rows based on the data order in the input dataset. C (ORDER=INTERNAL): Orders rows based on the internal SAS sort order, which may vary E (ORDER-FORMAT): Orders rows based on the format used for the variable.

NEW QUESTION # 82
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SASINSTITUTE A00-215 WEB-BASED PRACTICE EXAM

SASInstitute A00-215 Web-based Practice Exam